.TH BSoffset 3 "10/27/1995" " " "BlockSolve95"
.SH NAME
BSoffset \- Find a consistent global numbering

.SH INPUT PARAMETERS
.PD 0
.TP
.B length 
- number of classes of things to order
.PD 1
.PD 0
.TP
.B array 
- the number of things in each class on this processor
.PD 1
.PD 0
.TP
.B procinfo 
- the usual processor stuff
.PD 1

.SH OUTPUT PARAMETERS
.PD 0
.TP
.B offsets 
- the beginning number for each class on this processor
in the global numbering
.PD 1

.SH RETURNS
the number of classes across all the processors

.SH NOTES
This routine, given a list of totals, finds where we should be
numbered.  For example, if proc 0 submits a list of 10 and 20
and proc 1 submits a list of 5 and 11 and proc 2 submits a
list of 6 and 9, we want to do a tree ordering where
proc 0 gets back 5 and 32, proc 1 gets back 0 and 21 and
proc 2 gets back 15 and 52.

.SH SYNOPSIS
.nf
int BSoffset(int length, int *array, int **offsets, BSprocinfo *procinfo)

.fi

.SH LOCATION
 BlockSolve95/src/BSoffset.c