(* Title: ZF/AC/Cardinal_aux.thy ID: $Id: Cardinal_aux.thy,v 1.7 2005/06/17 14:15:10 haftmann Exp $ Author: Krzysztof Grabczewski Auxiliary lemmas concerning cardinalities *) theory Cardinal_aux imports AC_Equiv begin lemma Diff_lepoll: "[| A \ succ(m); B \ A; B\0 |] ==> A-B \ m" apply (rule not_emptyE, assumption) apply (blast intro: lepoll_trans [OF subset_imp_lepoll Diff_sing_lepoll]) done (* ********************************************************************** *) (* Lemmas involving ordinals and cardinalities used in the proofs *) (* concerning AC16 and DC *) (* ********************************************************************** *) (* j=|A| *) lemma lepoll_imp_ex_le_eqpoll: "[| A \ i; Ord(i) |] ==> \j. j le i & A \ j" by (blast intro!: lepoll_cardinal_le well_ord_Memrel well_ord_cardinal_eqpoll [THEN eqpoll_sym] dest: lepoll_well_ord) (* j=|A| *) lemma lesspoll_imp_ex_lt_eqpoll: "[| A \ i; Ord(i) |] ==> \j. j j" by (unfold lesspoll_def, blast dest!: lepoll_imp_ex_le_eqpoll elim!: leE) lemma Inf_Ord_imp_InfCard_cardinal: "[| ~Finite(i); Ord(i) |] ==> InfCard(|i|)" apply (unfold InfCard_def) apply (rule conjI) apply (rule Card_cardinal) apply (rule Card_nat [THEN Card_def [THEN def_imp_iff, THEN iffD1, THEN ssubst]]) -- "rewriting would loop!" apply (rule well_ord_Memrel [THEN well_ord_lepoll_imp_Card_le], assumption) apply (rule nat_le_infinite_Ord [THEN le_imp_lepoll], assumption+) done text{*An alternative and more general proof goes like this: A and B are both well-ordered (because they are injected into an ordinal), either A lepoll B or B lepoll A. Also both are equipollent to their cardinalities, so (if A and B are infinite) then A Un B lepoll |A|+|B| = max(|A|,|B|) lepoll i. In fact, the correctly strengthened version of this theorem appears below.*} lemma Un_lepoll_Inf_Ord_weak: "[|A \ i; B \ i; \ Finite(i); Ord(i)|] ==> A \ B \ i" apply (rule Un_lepoll_sum [THEN lepoll_trans]) apply (rule lepoll_imp_sum_lepoll_prod [THEN lepoll_trans]) apply (erule eqpoll_trans [THEN eqpoll_imp_lepoll]) apply (erule eqpoll_sym) apply (rule subset_imp_lepoll [THEN lepoll_trans, THEN lepoll_trans]) apply (rule nat_2I [THEN OrdmemD], rule Ord_nat) apply (rule nat_le_infinite_Ord [THEN le_imp_lepoll], assumption+) apply (erule eqpoll_sym [THEN eqpoll_imp_lepoll]) apply (erule prod_eqpoll_cong [THEN eqpoll_imp_lepoll, THEN lepoll_trans], assumption) apply (rule eqpoll_imp_lepoll) apply (rule well_ord_Memrel [THEN well_ord_InfCard_square_eq], assumption) apply (rule Inf_Ord_imp_InfCard_cardinal, assumption+) done lemma Un_eqpoll_Inf_Ord: "[| A \ i; B \ i; ~Finite(i); Ord(i) |] ==> A Un B \ i" apply (rule eqpollI) apply (blast intro: Un_lepoll_Inf_Ord_weak) apply (erule eqpoll_sym [THEN eqpoll_imp_lepoll, THEN lepoll_trans]) apply (rule Un_upper1 [THEN subset_imp_lepoll]) done lemma paired_bij: "?f \ bij({{y,z}. y \ x}, x)" apply (rule RepFun_bijective) apply (simp add: doubleton_eq_iff, blast) done lemma paired_eqpoll: "{{y,z}. y \ x} \ x" by (unfold eqpoll_def, fast intro!: paired_bij) lemma ex_eqpoll_disjoint: "\B. B \ A & B Int C = 0" by (fast intro!: paired_eqpoll equals0I elim: mem_asym) (*Finally we reach this result. Surely there's a simpler proof, as sketched above?*) lemma Un_lepoll_Inf_Ord: "[| A \ i; B \ i; ~Finite(i); Ord(i) |] ==> A Un B \ i" apply (rule_tac A1 = i and C1 = i in ex_eqpoll_disjoint [THEN exE]) apply (erule conjE) apply (drule lepoll_trans) apply (erule eqpoll_sym [THEN eqpoll_imp_lepoll]) apply (rule Un_lepoll_Un [THEN lepoll_trans], (assumption+)) apply (blast intro: eqpoll_refl Un_eqpoll_Inf_Ord eqpoll_imp_lepoll) done lemma Least_in_Ord: "[| P(i); i \ j; Ord(j) |] ==> (LEAST i. P(i)) \ j" apply (erule Least_le [THEN leE]) apply (erule Ord_in_Ord, assumption) apply (erule ltE) apply (fast dest: OrdmemD) apply (erule subst_elem, assumption) done lemma Diff_first_lepoll: "[| well_ord(x,r); y \ x; y \ succ(n); n \ nat |] ==> y - {THE b. first(b,y,r)} \ n" apply (case_tac "y=0", simp add: empty_lepollI) apply (fast intro!: Diff_sing_lepoll the_first_in) done lemma UN_subset_split: "(\x \ X. P(x)) \ (\x \ X. P(x)-Q(x)) Un (\x \ X. Q(x))" by blast lemma UN_sing_lepoll: "Ord(a) ==> (\x \ a. {P(x)}) \ a" apply (unfold lepoll_def) apply (rule_tac x = "\z \ (\x \ a. {P (x) }) . (LEAST i. P (i) =z) " in exI) apply (rule_tac d = "%z. P (z) " in lam_injective) apply (fast intro!: Least_in_Ord) apply (fast intro: LeastI elim!: Ord_in_Ord) done lemma UN_fun_lepoll_lemma [rule_format]: "[| well_ord(T, R); ~Finite(a); Ord(a); n \ nat |] ==> \f. (\b \ a. f`b \ n & f`b \ T) --> (\b \ a. f`b) \ a" apply (induct_tac "n") apply (rule allI) apply (rule impI) apply (rule_tac b = "\b \ a. f`b" in subst) apply (rule_tac [2] empty_lepollI) apply (rule equals0I [symmetric], clarify) apply (fast dest: lepoll_0_is_0 [THEN subst]) apply (rule allI) apply (rule impI) apply (erule_tac x = "\x \ a. f`x - {THE b. first (b,f`x,R) }" in allE) apply (erule impE, simp) apply (fast intro!: Diff_first_lepoll, simp) apply (rule UN_subset_split [THEN subset_imp_lepoll, THEN lepoll_trans]) apply (fast intro: Un_lepoll_Inf_Ord UN_sing_lepoll) done lemma UN_fun_lepoll: "[| \b \ a. f`b \ n & f`b \ T; well_ord(T, R); ~Finite(a); Ord(a); n \ nat |] ==> (\b \ a. f`b) \ a" by (blast intro: UN_fun_lepoll_lemma) lemma UN_lepoll: "[| \b \ a. F(b) \ n & F(b) \ T; well_ord(T, R); ~Finite(a); Ord(a); n \ nat |] ==> (\b \ a. F(b)) \ a" apply (rule rev_mp) apply (rule_tac f="\b \ a. F (b)" in UN_fun_lepoll) apply auto done lemma UN_eq_UN_Diffs: "Ord(a) ==> (\b \ a. F(b)) = (\b \ a. F(b) - (\c \ b. F(c)))" apply (rule equalityI) prefer 2 apply fast apply (rule subsetI) apply (erule UN_E) apply (rule UN_I) apply (rule_tac P = "%z. x \ F (z) " in Least_in_Ord, (assumption+)) apply (rule DiffI, best intro: Ord_in_Ord LeastI, clarify) apply (erule_tac P = "%z. x \ F (z) " and i = c in less_LeastE) apply (blast intro: Ord_Least ltI) done lemma lepoll_imp_eqpoll_subset: "a \ X ==> \Y. Y \ X & a \ Y" apply (unfold lepoll_def eqpoll_def, clarify) apply (blast intro: restrict_bij dest: inj_is_fun [THEN fun_is_rel, THEN image_subset]) done (* ********************************************************************** *) (* Diff_lesspoll_eqpoll_Card *) (* ********************************************************************** *) lemma Diff_lesspoll_eqpoll_Card_lemma: "[| A\a; ~Finite(a); Card(a); B \ a; A-B \ a |] ==> P" apply (elim lesspoll_imp_ex_lt_eqpoll [THEN exE] Card_is_Ord conjE) apply (frule_tac j=xa in Un_upper1_le [OF lt_Ord lt_Ord], assumption) apply (frule_tac j=xa in Un_upper2_le [OF lt_Ord lt_Ord], assumption) apply (drule Un_least_lt, assumption) apply (drule eqpoll_imp_lepoll [THEN lepoll_trans], rule le_imp_lepoll, assumption)+ apply (case_tac "Finite(x Un xa)") txt{*finite case*} apply (drule Finite_Un [OF lepoll_Finite lepoll_Finite], assumption+) apply (drule subset_Un_Diff [THEN subset_imp_lepoll, THEN lepoll_Finite]) apply (fast dest: eqpoll_sym [THEN eqpoll_imp_lepoll, THEN lepoll_Finite]) txt{*infinite case*} apply (drule Un_lepoll_Inf_Ord, (assumption+)) apply (blast intro: le_Ord2) apply (drule lesspoll_trans1 [OF subset_Un_Diff [THEN subset_imp_lepoll, THEN lepoll_trans] lt_Card_imp_lesspoll], assumption+) apply (simp add: lesspoll_def) done lemma Diff_lesspoll_eqpoll_Card: "[| A \ a; ~Finite(a); Card(a); B \ a |] ==> A - B \ a" apply (rule ccontr) apply (rule Diff_lesspoll_eqpoll_Card_lemma, (assumption+)) apply (blast intro: lesspoll_def [THEN def_imp_iff, THEN iffD2] subset_imp_lepoll eqpoll_imp_lepoll lepoll_trans) done end