# Copyright (c) 2003-2006 CORE Security Technologies

#

# This software is provided under under a slightly modified version

# of the Apache Software License. See the accompanying LICENSE file

# for more information.

#

# $Id: uuid.py,v 1.4 2006/05/23 21:19:26 gera Exp $

#

# Description:

#   Generate UUID compliant with http://www.webdav.org/specs/draft-leach-uuids-guids-01.txt.

#   A different, much simpler (not necessarily better) algorithm is used.

#

# Author:

#   Javier Kohen (jkohen)

#


import re

from random import randrange
from struct import pack, unpack

def generate():
    # UHm... crappy Python has an maximum integer of 2**31-1.

    top = (1L<<31)-1
    return pack("IIII", randrange(top), randrange(top), randrange(top), randrange(top))

def bin_to_string(uuid):
    uuid1, uuid2, uuid3 = unpack('<LHH', uuid[:8])
    uuid4, uuid5, uuid6 = unpack('>HHL', uuid[8:16])
    return '%08X-%04X-%04X-%04X-%04X%08X' % (uuid1, uuid2, uuid3, uuid4, uuid5, uuid6)

def string_to_bin(uuid):
    matches = re.match('([\dA-Fa-f]{8})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})-([\dA-Fa-f]{4})([\dA-Fa-f]{8})', uuid)
    (uuid1, uuid2, uuid3, uuid4, uuid5, uuid6) = map(lambda x: long(x, 16), matches.groups())
    uuid = pack('<LHH', uuid1, uuid2, uuid3)
    uuid += pack('>HHL', uuid4, uuid5, uuid6)
    return uuid

def stringver_to_bin(s):
    (maj,min) = s.split('.')
    return pack('<H',int(maj)) + pack('<H',int(min))

def uuidtup_to_bin(tup):
    if len(tup) != 2: return
    return string_to_bin(tup[0]) + stringver_to_bin(tup[1])

#input: string

#output: tuple (uuid,version) 

#if version is not found in the input string "1.0"  is returned

#example: 

#           "00000000-0000-0000-0000-000000000000 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0') 

#           "10000000-2000-3000-4000-500000000000 version 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0') 

#           "10000000-2000-3000-4000-500000000000 v 3.0" returns ('00000000-0000-0000-0000-000000000000','3.0') 

#           "10000000-2000-3000-4000-500000000000" returns ('00000000-0000-0000-0000-000000000000','1.0') 

def string_to_uuidtup(s):
    g =  re.search("([A-Fa-f0-9]{8}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{4}-[A-Fa-f0-9]{12}).*?([0-9]{1,5}\.[0-9]{1,5})",s+" 1.0")
    if g: 
        (u,v) = g.groups()
        return (u,v)
    return